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AP Biology • Unit 1 Chemistry of Life

AP Biology Unit 1.6–1.7: Nucleic Acids & Proteins

This interactive lesson turns the attached College Board material into a full AP Biology learning sequence focused on structure → interaction → function → consequence of change.

Topic 1.6 Nucleic AcidsTopic 1.7 ProteinsStructure–FunctionPredictionMCQ + FRQ

Learning objectives

AP habit: When asked to explain, name the structural feature or interaction first, then connect it to function.

Warm-up

1. Every nucleotide contains...
2. Which level of protein structure is the linear amino-acid sequence?

Part I — Nucleic Acids

1. Nucleotide structure

DNA and RNA are polymers made from nucleotide monomers. Each nucleotide contains a five-carbon sugar, phosphate group, and nitrogenous base.

Adjacent nucleotides are linked by covalent phosphodiester bonds, forming the sugar-phosphate backbone. Because the sugar is asymmetric, each strand has distinct 5′ and 3′ ends.

Remember: the backbone is covalent; complementary bases are held together by hydrogen bonds.
NucleotidePO₄SugarBasephosphatepentosenitrogenous baseNucleotides polymerize through phosphodiester bonds.

2. DNA vs RNA

FeatureDNARNA
SugarDeoxyriboseRibose
BasesA, T, C, GA, U, C, G
Typical organizationDouble-strandedUsually single-stranded
DirectionalityPaired strands are antiparallelHas 5′ and 3′ ends
BackboneSugar-phosphateSugar-phosphate
DNARNA5′3′3′5′ATGCAUCUsually single-stranded, but can foldinto complex shapes by internal base pairing.
Base pairing: DNA A–T and G–C pairing reflects molecular shape and hydrogen-bonding compatibility. Complementary strands run antiparallel.

Video 1 — DNA vs RNA

Focus questions

  1. List three similarities between DNA and RNA.
  2. Identify the sugar in each molecule.
  3. Which nitrogenous base differs?
  4. Why are 5′ and 3′ ends important?
  5. How can a single RNA strand form complex shape?

Part II — Proteins

3. Amino-acid structure

Every amino acid contains an α-carbon bonded to an amino group, carboxyl group, hydrogen, and a variable R group. The R group determines chemical properties such as charge, polarity, and hydrophobicity.

AP distinction: R groups drive many of the interactions that determine tertiary structure.
General amino acidCNH₂amino groupCOOHcarboxyl groupHRvariable side chain

4. Peptide bonds

A peptide bond forms between the carboxyl group of one amino acid and the amino group of another in a dehydration reaction. Repetition produces a polypeptide.

Peptide bond formationH₂N—CH—COOH|R₁+H₂N—CH—COOH|R₂dehydration → peptide bond + H₂O

5. Four levels of protein structure

LevelMeaningMajor interactions/featuresConsequence of disruption
PrimaryLinear amino-acid sequencePeptide bondsSequence change can alter later folding.
Secondaryα-helices and β-sheetsHydrogen bonds between backbone atomsLocal folding may be destabilized.
Tertiary3-D shape of one polypeptideHydrophobic interactions, hydrogen bonds, ionic interactions, van der Waals forces, disulfide bondsActive/binding sites can change.
QuaternaryAssociation of multiple polypeptidesInteractions among subunitsComplex function can be reduced or lost.
Primary → Secondary → Tertiary → QuaternaryPrimarySecondaryTertiaryQuaternarysequenceα-helix / β-sheet3-D foldmultiple subunits
Core idea: Primary structure influences folding; folding determines the geometry and chemistry of functional regions.

Video 2 — Protein Structure and Folding

Focus questions

  1. How does primary structure differ from secondary structure?
  2. Which interactions stabilize tertiary structure?
  3. Why do not all proteins have quaternary structure?
  4. How can denaturation affect function?
  5. Why can one amino-acid substitution have a large effect?

AP Biology Practice — Multiple Choice

1. A nucleic-acid polymer contains ribose and uracil. It is most likely...
2. Which change most directly alters primary protein structure?
3. An enzyme loses function at high temperature but its peptide bonds remain intact. The most likely explanation is...
4. Which statement correctly distinguishes peptide bonds from hydrogen bonds in proteins?
5. A mutation prevents one polypeptide subunit from associating with three others. Which level is most directly affected?
6. Which structural feature allows some RNA molecules to fold into complex shapes?
7. A surface amino acid changes from negatively charged to positively charged. Which outcome is most plausible?
8. Why do DNA bases pair specifically?
9. Complete hydrolysis of a protein yields mostly...
10. A one-amino-acid substitution does not change a protein's function. Which explanation is most reasonable?
11. A DNA strand is 5′-A G C T A-3′. Which complementary strand is correctly written antiparallel?
12. Which change is most likely to disrupt a protein's tertiary structure without directly breaking peptide bonds?

Data Analysis — Enzyme Stability

A researcher incubates an enzyme for 10 minutes at different temperatures and then measures activity.

Temperature (°C)Relative activity (%)
2068
3092
40100
5061
6018
703
  1. Describe the trend from 20–40°C.
  2. Describe the trend from 40–70°C.
  3. Explain the decline above 40°C using protein structure.
  4. Predict whether cooling the 70°C sample back to 40°C must restore activity. Justify.
Activity rises to an optimum near 40°C and then falls sharply. High temperature can disrupt noncovalent interactions that stabilize protein folding, changing the active-site shape. Cooling may not restore activity if denaturation or aggregation is irreversible.

AP-Style FRQ Practice

FRQ 1 — Hemoglobin structure

Hemoglobin contains multiple polypeptide subunits. A mutation prevents one subunit from associating with the others.

(a) Identify the level of structure most directly affected. [1]
(b) Predict the effect on oxygen-binding function. [1]
(c) Justify the prediction using structure–function reasoning. [2]

(a) Quaternary structure. (b) Oxygen binding/release is likely to be altered or reduced. (c) Hemoglobin function depends on interactions among subunits; loss of a subunit changes the assembled structure and therefore the functional geometry/cooperativity of oxygen binding.

FRQ 2 — Mutation and folding

A mutation replaces a hydrophobic amino acid buried in a protein interior with a charged amino acid.

(a) Predict the effect on tertiary structure. [2]
(b) Explain how function could change. [2]
(c) Describe one measurement that could test whether the protein changed. [1]

The charged side chain is less favorable in a hydrophobic interior and may form new ionic/hydrogen-bonding interactions, changing folding. A changed 3-D shape can alter binding or catalytic sites. Valid tests include enzyme activity, ligand-binding affinity, thermal stability, protease sensitivity, or spectroscopy.

FRQ 3 — DNA/RNA model

Polymer X is double-stranded and contains thymine. Polymer Y is single-stranded and contains uracil.

(a) Identify X and Y. [2]
(b) State one shared structural feature. [1]
(c) Explain how nucleotide chemistry produces 5′→3′ directionality. [2]

X is DNA; Y is RNA. Both are nucleotide polymers with sugar-phosphate backbones. Directionality arises because phosphodiester bonds connect the 5′ phosphate region of one nucleotide to the 3′ hydroxyl of the next.

FRQ 4 — Experimental design

A student claims that changing pH alters enzyme activity because it changes interactions that stabilize tertiary structure. Design an experiment that includes the independent variable, dependent variable, one controlled variable, and the expected result pattern that would support the claim. [4]

Vary pH while holding enzyme concentration, substrate concentration, temperature, and reaction time constant. Measure reaction rate. A pH-dependent activity curve with reduced activity away from an optimum supports the idea that altered side-chain protonation disrupts interactions required for functional shape.

FRQ 5 — Claim, Evidence, Reasoning

Evaluate the claim: “A mutation that changes one amino acid can change phenotype even when the rest of the protein sequence is unchanged.” Use molecular evidence and reasoning.

Claim: The substitution can change phenotype. Evidence: R-group properties influence protein interactions and folding. Reasoning: A changed interaction can alter tertiary/quaternary structure, which can change molecular function and therefore a cellular or organismal trait.

Exit Ticket

  1. Give two similarities and two differences between DNA and RNA.
  2. Explain why peptide bonds define primary structure but do not alone define tertiary structure.
  3. Explain how an R-group substitution can alter protein function.
  4. Predict what may happen if one subunit of a multimeric protein can no longer bind the others.
  5. Write one remaining question you have about nucleic acids or proteins.

Self-Assessment

DNA vs RNA
Nucleotide structure
Amino acids & peptide bonds
Protein structure levels
Predicting effects of mutations
FRQ reasoning